Key Points

Areas Related To Circles

13 Sections
  • Sector of a Circle

    A sector is the portion of a circular region enclosed by two radii and the corresponding arc. The smaller area is the minor sector and the larger area is the major sector.

  • Segment of a Circle

    A segment is the portion of a circular region enclosed between a chord and the corresponding arc. The smaller area is the minor segment, and the larger one is the major segment.

  • Area of a Sector

    The area of a sector with angle θ\theta (in degrees) and radius rr is given by the formula: Area =θ360×πr2= \frac{\theta}{360} \times \pi r^2. The area is proportional to the central angle.

  • Length of an Arc

    The length of an arc of a sector with angle θ\theta (in degrees) and radius rr is calculated as: Arc Length =θ360×2πr= \frac{\theta}{360} \times 2 \pi r. This is a fraction of the total circumference.

  • Area of a Segment

    The area of a segment is found by subtracting the area of the corresponding triangle from the area of the sector. Area of Segment = Area of Sector OAPB - Area of \triangle OAB.

  • Calculating Triangle Area in a Sector

    To find the area of the triangle (e.g., \triangle OAB) formed by the two radii and the chord, you can use trigonometry or geometric properties. For an angle θ\theta and radius rr, the area is 12r2sinθ\frac{1}{2} r^2 \sin \theta.

  • Triangle Area for Angle 60 Degrees

    When the central angle of a sector is 6060^\circ, the triangle formed by the two radii and the chord is an equilateral triangle. Its area is 34r2\frac{\sqrt{3}}{4} r^2, where rr is the radius.

  • Triangle Area for Angle 90 Degrees

    When the central angle is 9090^\circ (a quadrant), the triangle formed is a right-angled isosceles triangle. Its area is 12×base×height=12r2\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} r^2.

  • Area of a Major Sector

    The area of a major sector can be found in two ways. Either subtract the minor sector's area from the total circle's area: πr2Area of Minor Sector\pi r^2 - \text{Area of Minor Sector}, or use the reflex angle (360θ)(360^\circ - \theta) in the sector formula.

  • Area of a Major Segment

    The area of a major segment is calculated by subtracting the area of the minor segment from the total area of the circle. Area of Major Segment =πr2Area of Minor Segment= \pi r^2 - \text{Area of Minor Segment}.

  • Area of a Quadrant

    A quadrant of a circle is a sector with a central angle of 9090^\circ. Its area is exactly one-fourth of the total area of the circle, given by the formula Area =14πr2= \frac{1}{4} \pi r^2.

  • Area Swept by a Clock Hand

    The area swept by a minute hand in a given time is the area of a sector. The length of the hand is the radius rr. The angle is found by knowing the minute hand moves 360360^\circ in 60 minutes, which is 66^\circ per minute.

  • Alternative Sector Area Formula

    The formula for the area of a sector, θ360×πr2\frac{\theta}{360} \times \pi r^2, can sometimes be written as θ720×2πr2\frac{\theta}{720} \times 2 \pi r^2. Both forms are equivalent and give the same result.

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