Biotechnology : Principles and ProcessesClass 12 Biology NCERT Solutions
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Q1EXERCISES
Can you list 10 recombinant proteins which are used in medical practice? Find out where they are used as therapeutics (use the internet).
Solution
Ten recombinant proteins used in medical practice and their therapeutic uses are:
- Human Insulin (Humulin): Used for the treatment of diabetes mellitus to control blood sugar levels.
- Human Growth Hormone (Somatotropin): Used to treat pituitary dwarfism in children and growth hormone deficiency in adults.
- Erythropoietin: Used to stimulate the formation of red blood cells in patients suffering from anemia, especially during kidney failure or chemotherapy.
- Tissue Plasminogen Activator (tPA): Used as a 'clot buster' to dissolve blood clots in patients who have had a heart attack or stroke.
- Interferon-: Used for the treatment of certain viral infections like hepatitis C and some types of cancer like hairy-cell leukemia.
- Blood Clotting Factor VIII: Used for the treatment of Hemophilia A, a genetic disorder that impairs blood clotting.
- Blood Clotting Factor IX: Used for the treatment of Hemophilia B.
- Hepatitis B Vaccine: A recombinant protein (HBsAg) produced in yeast, used for immunization to prevent Hepatitis B infection.
- Interleukin-2: Used in cancer immunotherapy to stimulate the activity of immune cells (T-cells) to fight cancer.
- DNase I (Pulmozyme): Used in the treatment of cystic fibrosis to break down DNA in the thick mucus in the lungs, making it easier to clear.
Q2EXERCISES
Make a chart (with diagrammatic representation) showing a restriction enzyme, the substrate DNA on which it acts, the site at which it cuts DNA and the product it produces.
Solution
Here is a chart for the restriction enzyme EcoRI, as described in the chapter:
| Feature | Description |
|---|---|
| Restriction Enzyme | EcoRI |
| Source Organism | Escherichia coli RY 13 |
| Substrate DNA | A double-stranded DNA molecule. |
| Recognition Site | A specific 6 base-pair palindromic sequence: |
| Site of Action (Cut) | The enzyme cuts the phosphodiester backbone between the Guanine (G) and Adenine (A) bases on both strands. |
| $5'—\text{G} | \text{AATTC}—3'$ |
| $3'—\text{CTTAA} | \text{G}—5'$ |
| Product | Two DNA fragments with single-stranded, overhanging 'sticky ends'. These ends are complementary and can form hydrogen bonds with other DNA fragments cut by the same enzyme. |
| Fragment 1: | |
| Fragment 2: |
$3'—\text{CTTAA}$ $3'—\text{G}$ |
(This process is illustrated in Figure 9.1 of the textbook).
Q3EXERCISES
From what you have learnt, can you tell whether enzymes are bigger or DNA is bigger in molecular size? How did you know?
Solution
DNA molecules are significantly bigger than enzyme molecules in molecular size.
Reasoning:
- Composition and Structure: DNA is a macromolecule composed of millions or even billions of nucleotide pairs that make up a chromosome. Enzymes are proteins, which are polymers of amino acids, typically consisting of a few hundred to a few thousand amino acids.
- Scale of Interaction: The chapter explains that a restriction enzyme 'inspects' the length of a DNA sequence to find its specific recognition site. This implies that the enzyme is a smaller entity that moves along a much larger DNA molecule. The enzyme acts on a very small portion (e.g., a 6 base-pair sequence) of the entire DNA molecule.
- Molecular Weight: The molecular weight of a single human chromosome can be in the range of billions of daltons, whereas the molecular weight of a typical enzyme like EcoRI is in the range of thousands of daltons. Therefore, a DNA molecule is vastly larger and more massive than an enzyme molecule.
Q4EXERCISES
What would be the molar concentration of human DNA in a human cell? Consult your teacher.
Solution
Calculating the precise molar concentration of DNA in a human cell is complex and depends on several assumptions. Here is an estimation based on typical values:
- Amount of DNA: A diploid human cell contains approximately base pairs (bp).
- Molar Mass of a Base Pair: The average molecular weight of a base pair is approximately 650 g/mol.
- Total Mass of DNA: The total mass of DNA in a single cell can be calculated: Mass = (Number of bp) (Avg. mass per bp) / (Avogadro's number) Mass ( bp) (650 g/mol/bp) / ( molecules/mol) g.
- Volume of the Nucleus: The DNA is contained within the nucleus. A typical human nucleus has a diameter of about 6 µm. Assuming it is a sphere: Radius (r) = 3 µm = cm Volume (V) = L.
- Molar Concentration: Molarity is moles per liter. In this context, we can consider the entire genome (all 46 chromosomes) as a set. The number of moles of this 'set' in one cell is 1 / Avogadro's number. Moles = mol. Molar Concentration = Moles / Volume = ( mol) / ( L) M.
Conclusion: The molar concentration of DNA within the nucleus is extremely low, on the order of M. However, it is important to note that the DNA is not dissolved but is highly condensed and organized by proteins like histones.
Q5EXERCISES
Do eukaryotic cells have restriction endonucleases? Justify your answer.
Solution
No, eukaryotic cells do not have restriction endonucleases.
Justification:
- Origin and Function: As stated in the chapter, restriction endonucleases were isolated from prokaryotic organisms like bacteria (e.g., Escherichia coli). In bacteria, these enzymes are part of a defense mechanism called the restriction-modification system, which protects the bacterium from invading viruses (bacteriophages) by cutting the foreign viral DNA.
- Self-DNA Protection: Bacteria protect their own DNA from being cut by their restriction enzymes by modifying it, usually through methylation at the recognition sites.
- Eukaryotic Defense: Eukaryotic organisms have more complex and advanced defense mechanisms against viruses, such as the immune system in animals and RNA interference (RNAi) in many eukaryotes. They do not rely on a restriction-modification system for defense.
- Absence of Evidence: Restriction endonucleases are characteristically found in prokaryotes, and there is no evidence of their natural presence or function within eukaryotic cells.
Q6EXERCISES
Besides better aeration and mixing properties, what other advantages do stirred tank bioreactors have over shake flasks?
Solution
Besides better aeration and mixing, stirred-tank bioreactors have several advantages over simple shake flasks for large-scale production:
- Process Control: Bioreactors are equipped with automated control systems to monitor and maintain optimal growth conditions. This includes sensors and regulators for temperature, pH, and dissolved oxygen, ensuring consistency and maximizing yield.
- Large-Scale Production: Bioreactors are designed for large volumes (100-1000 litres or more), allowing for the production of commercially significant quantities of a product. Shake flasks are limited to small, laboratory-scale volumes.
- Sterility and Aseptic Operation: Bioreactors are designed as closed systems that can be sterilized and maintained in a sterile (aseptic) condition for long periods, preventing contamination which is a major risk in large-scale cultures.
- Continuous Culture System: They can be operated as a continuous culture system, where fresh medium is continuously added and used medium is drained out. This keeps the cells in the physiologically active log/exponential phase, leading to higher productivity over a longer time.
- Sampling Ports: Bioreactors have sampling ports that allow for the sterile withdrawal of small volumes of the culture for periodic testing and quality control without contaminating the entire batch.
- Foam Control: They often include a foam control system or foam breaker, which is essential as protein-rich culture media can produce significant foam during agitation and aeration, which can interfere with the process.
Q7EXERCISES
Collect 5 examples of palindromic DNA sequences by consulting your teacher. Better try to create a palindromic sequence by following base-pair rules.
Solution
A palindromic DNA sequence is a sequence of base pairs that reads the same on the two strands when the orientation of reading () is kept the same. Here are 5 examples, which are recognition sites for common restriction enzymes:
-
EcoRI:
-
BamHI:
-
HindIII:
-
HaeIII:
-
SalI:
Q8EXERCISES
Can you recall meiosis and indicate at what stage a recombinant DNA is made?
Solution
Yes, in the context of natural genetic recombination during meiosis, recombinant DNA is formed during Prophase I.
Specifically, this occurs in the pachytene stage of Prophase I. During this stage, homologous chromosomes are paired up (a structure called a bivalent). Non-sister chromatids of these homologous chromosomes physically cross over each other at points called chiasmata. At these points, segments of DNA are exchanged between the chromatids. This process, known as crossing over, results in the formation of new combinations of alleles on the chromosomes. The resulting chromatids contain a mixture of paternal and maternal genetic material and are therefore considered naturally 'recombinant DNA'.
It is important to distinguish this natural process from the artificial construction of a recombinant DNA molecule in the laboratory using tools like restriction enzymes and ligases, which is the central theme of this chapter.
Q9EXERCISES
Can you think and answer how a reporter enzyme can be used to monitor transformation of host cells by foreign DNA in addition to a selectable marker?
Solution
A reporter enzyme can be used to differentiate between recombinant and non-recombinant cells through a process called insertional inactivation, often referred to as blue-white screening. This method works in addition to a selectable marker that selects for transformants.
Here is how it works:
- Vector Design: The cloning vector is engineered to contain a selectable marker (e.g., an ampicillin resistance gene, ) and a reporter gene (e.g., lacZ, which codes for the enzyme -galactosidase). The multiple cloning site (where foreign DNA is to be inserted) is located within the lacZ gene.
- Ligation: When a foreign DNA fragment is successfully ligated into the cloning site, it disrupts the coding sequence of the lacZ gene, rendering it non-functional. This is called insertional inactivation.
- Transformation and Selection: The mixture of plasmids (recombinant and non-recombinant) is introduced into host cells. The cells are then plated on a medium containing the antibiotic (e.g., ampicillin) and a chromogenic substrate for the reporter enzyme (e.g., X-gal for -galactosidase).
- Screening:
- Transformants vs. Non-transformants: Only cells that have taken up a plasmid (either recombinant or non-recombinant) will survive because they have the ampicillin resistance gene. Non-transformed cells will die.
- Recombinants vs. Non-recombinants:
- Non-recombinant colonies (Blue): Cells that took up a plasmid without the foreign DNA insert have a functional lacZ gene. They produce -galactosidase, which cleaves the X-gal substrate, resulting in blue-colored colonies.
- Recombinant colonies (White): Cells that took up a plasmid with the foreign DNA insert have an inactivated lacZ gene. They do not produce functional -galactosidase, so X-gal is not cleaved, and the colonies remain white.
Thus, by simply observing the color of the colonies, one can easily identify and select the recombinant host cells.
Q10EXERCISES
Describe briefly the following:
(a)
Origin of replication
(b)
Bioreactors
(c)
Downstream processing
Solution
(a) Origin of replication (ori): This is a specific DNA sequence in a genome (on a chromosome or plasmid) from which DNA replication initiates. For a piece of foreign DNA to be replicated and multiplied in a host cell, it must be linked to an 'ori' sequence. The origin of replication also controls the copy number of the linked DNA; some 'ori' sequences support a high copy number, while others support a low copy number.
(b) Bioreactors: Bioreactors are large-scale vessels (typically 100-1000 litres) in which raw materials are biologically converted into specific products like enzymes, proteins, or other organic compounds using microbial, plant, or animal cells. They are designed to provide optimal growth conditions, including controlled temperature, pH, substrate availability, salts, vitamins, and oxygen. Stirred-tank bioreactors, the most common type, use an agitator for mixing and an oxygen delivery system to ensure uniform conditions for high-yield production.
(c) Downstream processing: This refers to the series of processes that a product undergoes after the biosynthetic or fermentation stage in a bioreactor is complete. It involves the separation and purification of the desired product from the culture medium, cell debris, and other impurities. The purified product is then formulated with suitable preservatives and subjected to strict quality control testing. In the case of drugs, it also includes clinical trials before the product is ready for marketing.
Q11EXERCISES
Explain briefly
(a)
PCR
(b)
Restriction enzymes and DNA
(c)
Chitinase
Solution
(a) PCR (Polymerase Chain Reaction): PCR is a laboratory technique used to amplify a specific segment of DNA, creating millions to billions of copies in vitro. The process involves a cycle of three steps:
1. Denaturation: The double-stranded DNA is heated (typically to ) to separate it into two single strands.
2. Annealing: The temperature is lowered () to allow short, chemically synthesized DNA primers to bind (anneal) to their complementary sequences on the single-stranded templates.
3. Extension: The temperature is raised (usually to ), and a thermostable DNA polymerase (like Taq polymerase) synthesizes a new DNA strand by extending the primers, using the original strand as a template. Repeating this cycle 25-35 times results in an exponential amplification of the target DNA segment.
(b) Restriction enzymes and DNA: Restriction enzymes, or restriction endonucleases, are proteins that act as 'molecular scissors' to cut DNA at specific sites. Each enzyme recognizes a unique, short sequence of nucleotides known as a recognition site. After binding to this site, the enzyme cuts the sugar-phosphate backbone of the DNA. Many restriction enzymes make staggered cuts, producing fragments with single-stranded overhangs called 'sticky ends'. These sticky ends can form hydrogen bonds with complementary sticky ends on other DNA fragments, facilitating the creation of recombinant DNA molecules by joining DNA from different sources.
(c) Chitinase: Chitinase is a digestive enzyme that breaks down chitin, a complex polysaccharide that forms the primary structural component of the cell walls of fungi. In biotechnology, chitinase is used during the first step of DNA isolation from fungal cells. To access the DNA inside the cell, the rigid cell wall must be disrupted. Treating the fungal cells with chitinase effectively digests the cell wall, releasing the cellular contents, including the DNA, for further purification.
Q12EXERCISES
Discuss with your teacher and find out how to distinguish between
(a)
Plasmid DNA and Chromosomal DNA
(b)
RNA and DNA
(c)
Exonuclease and Endonuclease
Solution
(a) Plasmid DNA vs. Chromosomal DNA
| Feature | Plasmid DNA | Chromosomal DNA |
|---|---|---|
| Location | In the cytoplasm (extra-chromosomal). | In the nucleoid (prokaryotes) or nucleus (eukaryotes). |
| Size | Small, typically a few thousand to a few hundred thousand base pairs. | Very large, millions to billions of base pairs. |
| Shape | Usually circular. | Circular in prokaryotes, linear in eukaryotes. |
| Genes | Carries non-essential but often beneficial genes (e.g., antibiotic resistance). | Carries all the essential genes required for the organism's survival and reproduction. |
| Replication | Replicates independently of the chromosomal DNA. | Replicates once per cell division cycle. |
| Copy Number | Can exist in multiple copies per cell (from 1 to over 100). | Typically exists as a single copy (or two in diploid cells before replication). |
(b) RNA vs. DNA
| Feature | RNA (Ribonucleic Acid) | DNA (Deoxyribonucleic Acid) |
|---|---|---|
| Structure | Usually single-stranded. | Double-stranded helix. |
| Sugar | Ribose. | Deoxyribose. |
| Nitrogenous Bases | Adenine (A), Guanine (G), Cytosine (C), Uracil (U). | Adenine (A), Guanine (G), Cytosine (C), Thymine (T). |
| Function | Multiple roles: mRNA (carries genetic code), tRNA (protein synthesis), rRNA (ribosome component). | Stores and transmits genetic information. |
| Stability | Chemically less stable and typically short-lived in the cell. | Chemically more stable, making it suitable for long-term genetic storage. |
(c) Exonuclease vs. Endonuclease
Both are nucleases, enzymes that cleave the phosphodiester bonds in nucleic acid molecules.
| Feature | Exonuclease | Endonuclease |
|---|---|---|
| Site of Action | Removes nucleotides one by one from the ends (either 5' or 3' end) of a nucleic acid strand. | Cleaves phosphodiester bonds at specific sites within a nucleic acid strand. |
| Product | Produces individual nucleotides and a shortened nucleic acid strand. | Produces smaller nucleic acid fragments. |
| Example | Exonuclease I. | Restriction enzymes (like EcoRI, HindII) and DNase I. |