Coordination Compounds
Coordination compounds are central to modern inorganic chemistry and are found everywhere, from industrial processes to the very molecules that sustain life. Transition metals, in particular, form a vast number of these complex compounds where a central metal atom is bonded to several surrounding anions or neutral molecules.
Many vital biological substances are coordination compounds. For instance, chlorophyll (a magnesium compound) is essential for photosynthesis, haemoglobin (an iron compound) carries oxygen in our blood, and vitamin B₁₂ (a cobalt compound) is crucial for our health. They also have numerous applications in metallurgy, industry, and medicine.
The foundational understanding of coordination compounds comes from the work of Swiss chemist Alfred Werner. He proposed that metal ions have two types of valencies:
CrCl₃, the primary valence of Cr is 3.Werner's theory was developed by studying compounds like cobalt(III) chloride with ammonia. He observed that when silver nitrate (AgNO₃) was added to solutions of these compounds, different amounts of silver chloride (AgCl) precipitated.
CoCl₃·6NH₃ (Yellow) produced 3 moles of AgCl.CoCl₃·5NH₃ (Purple) produced 2 moles of AgCl.CoCl₃·4NH₃ (Green or Violet) produced 1 mole of AgCl.These results suggested that some chloride ions were tightly bound to the cobalt ion, while others were free to ionize and react. Werner proposed that the groups inside a square bracket [] form a single unit (the coordination sphere) that does not break apart in solution. The ions outside the bracket are counter ions.
| Colour | Formula | Solution Conductivity |
|---|---|---|
| Yellow | [Co(NH₃)₆]³⁺ 3Cl⁻ | 1:3 electrolyte |
| Purple | [CoCl(NH₃)₅]²⁺ 2Cl⁻ | 1:2 electrolyte |
| Green | [CoCl₂(NH₃)₄]⁺ Cl⁻ | 1:1 electrolyte |
| Violet | [CoCl₂(NH₃)₄]⁺ Cl⁻ | 1:1 electrolyte |
Main Postulates of Werner's Theory:
Both double salts and complexes are formed from two or more stable compounds. However, their behavior in water is different.
FeSO₄·(NH₄)₂SO₄·6H₂O), dissociates completely into its constituent ions when dissolved in water.K₄[Fe(CN)₆]), contains a complex ion ([Fe(CN)₆]⁴⁻) that does not dissociate into its components (Fe²⁺ and CN⁻) in water.A coordination entity is a central metal atom or ion bonded to a fixed number of molecules or ions, called ligands. It is usually enclosed in square brackets.
[CoCl₃(NH₃)₃], [Ni(CO)₄], [Fe(CN)₆]⁴⁻.The central atom or ion is the atom/ion to which the ligands are attached in a definite geometric arrangement. Since it accepts electron pairs from ligands, it acts as a Lewis acid.
Ni²⁺ in [NiCl₂(H₂O)₄], Co³⁺ in [CoCl(NH₃)₅]²⁺.Ligands are the ions or molecules that bind to the central atom/ion in a coordination entity. They are electron-pair donors, acting as Lewis bases.
Ligands are classified based on the number of donor atoms they use to bind to the central metal, a property called denticity.
Cl⁻, H₂O, NH₃.en or H₂NCH₂CH₂NH₂), oxalate (C₂O₄²⁻).EDTA⁴⁻), which is a hexadentate ligand.NO₂⁻ ion can bind through Nitrogen (-NO₂) or Oxygen (-ONO).SCN⁻ ion can bind through Sulphur (-SCN) or Nitrogen (-NCS).The coordination number (CN) is the number of ligand donor atoms to which the central metal is directly bonded. It is determined by the number of sigma (σ) bonds formed between the metal and ligands.
[PtCl₆]²⁻, the CN of Pt is 6. In [Ni(NH₃)₄]²⁺, the CN of Ni is 4. In [Co(en)₃]³⁺, the CN of Co is 6 (since en is didentate and there are three en ligands, ).The coordination sphere consists of the central metal atom/ion and the ligands attached to it. It is written inside square brackets []. The ionisable groups written outside the brackets are called counter ions.
K₄[Fe(CN)₆], the coordination sphere is [Fe(CN)₆]⁴⁻ and the counter ion is K⁺.The coordination polyhedron is the spatial arrangement of the ligand atoms directly attached to the central atom/ion. Common shapes include octahedral, square planar, and tetrahedral.
The oxidation number is the charge the central atom would have if all ligands were removed along with the electron pairs they shared. It is written as a Roman numeral in parentheses after the name of the metal.
[Cu(CN)₄]³⁻, the oxidation number of copper is +1, written as Cu(I).[Co(NH₃)₆]³⁺.[Co(NH₃)₄Cl₂]⁺.An unambiguous system of naming is essential, especially for isomers. The International Union of Pure and Applied Chemistry (IUPAC) provides the rules.
[].().[Co(CN)₆]³⁻).Cl⁻ is chlorido, CN⁻ is cyanido).H₂O: aquaNH₃: ammineCO: carbonylNO: nitrosyl[NiCl₂(PPh₃)₂] is named dichlorido**bis(triphenylphosphine)**nickel(II).(a) The coordination sphere contains cobalt (Co), four ammine (NH₃), one aqua (H₂O), and one chlorido (Cl) ligand. Ligands are listed alphabetically: ammine, aqua, chlorido. The formula is [Co(NH₃)₄(H₂O)Cl]. The oxidation state of Co is +3. Charges: Co(+3) + NH₃(0) + H₂O(0) + Cl(-1) = +2. To balance this +2 charge, two chloride counter ions are needed.
Final Answer: [Co(NH₃)₄(H₂O)Cl]Cl₂
(b) The complex is an anion (name ends in -ate). Central atom is zinc (Zn) with four hydroxido (OH) ligands. The formula is [Zn(OH)₄]. Oxidation state of Zn is +2. Charges: Zn(+2) + 4OH(-1) = -2. To balance this -2 charge, two potassium (K⁺) cations are needed.
Final Answer: K₂[Zn(OH)₄]
(c) The complex is an anion. Central atom is aluminum (Al) with three oxalato (C₂O₄) ligands. The formula is [Al(C₂O₄)₃]. Oxidation state of Al is +3. Charges: Al(+3) + 3C₂O₄(-2) = -3. Three potassium (K⁺) ions are needed.
Final Answer: K₃[Al(C₂O₄)₃]
(d) The complex is a cation. Central atom is cobalt (Co) with two chlorido (Cl) and two ethane-1,2-diamine (en) ligands. The formula is [CoCl₂(en)₂]. Oxidation state of Co is +3. Charges: Co(+3) + 2Cl(-1) + 2en(0) = +1.
Final Answer: [CoCl₂(en)₂]⁺
(e) The complex is neutral. Central atom is nickel (Ni) with four carbonyl (CO) ligands. Oxidation state of Ni is 0.
Final Answer: [Ni(CO)₄]
[Pt(NH₃)₂Cl(NO₂)]
(b) K₃[Cr(C₂O₄)₃]
(c) [CoCl₂(en)₂]Cl
(d) [Co(NH₃)₅(CO₃)]Cl
(e) Hg[Co(SCN)₄](a) The complex is neutral. Ligands are ammine, chlorido, and nitrito. NO₂ is an ambidentate ligand, and here it's specified as nitrito-N (binding through nitrogen). Alphabetical order: ammine, chlorido, nitrito-N. Metal is platinum. Let oxidation state of Pt be x. .
Final Answer: diamminechloridonitrito-N-platinum(II)
(b) The cation is potassium. The anion is the complex sphere. Ligand is oxalate (C₂O₄²⁻). Since there are three, the prefix is tri-. The metal is chromium, and since it's in an anion, it becomes chromate. Let oxidation state of Cr be x. .
Final Answer: potassium trioxalatochromate(III)
(c) The cation is the complex sphere. Ligands are chlorido and ethane-1,2-diamine (en). There are two of each. The prefix for en is bis- because its name contains di-. Alphabetical order: chlorido, ethane-1,2-diamine. Metal is cobalt. The counter ion is chloride. Let oxidation state of Co be x. .
Final Answer: dichloridobis(ethane-1,2-diamine)cobalt(III) chloride
(d) The cation is the complex sphere. Ligands are ammine and carbonate (CO₃²⁻). Alphabetical order: ammine, carbonato. Metal is cobalt. Counter ion is chloride. Let oxidation state of Co be x. .
Final Answer: pentaamminecarbonatocobalt(III) chloride
(e) The cation is mercury (Hg). The anion is the complex sphere. The ligand is thiocyanate (SCN⁻), which is ambidentate. Here it is tetrathiocyanato-S (binding through sulfur). The metal is cobalt, and in an anion it becomes cobaltate. Let oxidation state of Co be x. The charge on [Co(SCN)₄] is -1 if Hg is +1, or -2 if Hg is +2. Let's assume Hg is +1. Then . A +3 oxidation state for Co is reasonable. If Hg is +2, . Let's check the source example, it implies Mercury(I) and Cobalt(III).
Final Answer: mercury(I) tetrathiocyanato-S-cobaltate(III)
Isomers are compounds that have the same chemical formula but different arrangements of atoms, leading to different physical or chemical properties. There are two main types of isomerism in coordination compounds.
This isomerism arises in heteroleptic complexes due to different possible geometric arrangements of the ligands. It is common in square planar and octahedral complexes.
Square Planar Complexes: In a complex of the formula [MX₂L₂], the two X ligands can be:
Octahedral Complexes: In a complex of the formula [MX₂L₄], the two X ligands can also be arranged in cis or trans positions.
In octahedral complexes of the formula [Ma₃b₃], two isomers are possible:
Optical isomers are non-superimposable mirror images of each other, like your left and right hands. These molecules are called chiral, and the pair of isomers are called enantiomers.
[Co(en)₃]³⁺.[PtCl₂(en)₂]²⁺, only the cis-isomer is chiral and shows optical activity. The trans-isomer is symmetrical and not optically active.[CrCl₂(ox)₂]³⁻
(b) trans-[CrCl₂(ox)₂]³⁻To determine if a molecule is chiral, we check if it is superimposable on its mirror image. (a) The cis-isomer lacks a plane of symmetry and is not superimposable on its mirror image. Therefore, it is chiral. (b) The trans-isomer has a plane of symmetry, making it superimposable on its mirror image. Therefore, it is not chiral (it is achiral).
Final Answer (a) cis-[CrCl₂(ox)₂]³⁻ is chiral (optically active).
This occurs when a complex contains an ambidentate ligand, which can bind to the metal through different atoms.
[Co(NH₃)₅(NO₂)]Cl₂ exists in two forms:
-ONO).-NO₂).This arises from the interchange of ligands between the cationic and anionic coordination entities in a complex salt.
[Co(NH₃)₆][Cr(CN)₆] and [Cr(NH₃)₆][Co(CN)₆] are coordination isomers. In the first, NH₃ is with Co and CN⁻ is with Cr; in the second, they are swapped.This occurs when the counter ion in a complex salt is itself a potential ligand and can displace a ligand from the coordination sphere. The isomers give different ions in solution.
[Co(NH₃)₅(SO₄)]Br and [Co(NH₃)₅Br]SO₄.
Br⁻ ions in solution (precipitates with AgNO₃).SO₄²⁻ ions in solution (precipitates with BaCl₂).This is similar to ionisation isomerism but involves solvent molecules. When water is the solvent, it's called hydrate isomerism. Isomers differ by whether a solvent molecule is directly bonded to the metal or is present as a free molecule in the crystal lattice.
[Cr(H₂O)₆]Cl₃ (violet) and its solvate isomer [Cr(H₂O)₅Cl]Cl₂·H₂O (grey-green).VBT explains the formation and structure of coordination compounds based on hybridization of the metal's atomic orbitals.
Key Concepts:
| Coordination Number | Type of Hybridisation | Geometry |
|---|---|---|
| 4 | sp³ | Tetrahedral |
| 4 | dsp² | Square planar |
| 6 | d²sp³ | Octahedral |
| 6 | sp³d² | Octahedral |
Inner vs. Outer Orbital Complexes (for Octahedral Geometry):
(n-1)d orbitals for hybridization (d²sp³). These are often low spin complexes because electrons are forced to pair up to free the inner d-orbitals.nd orbitals for hybridization (sp³d²). These are often high spin complexes because inner d-electrons remain unpaired.Examples:
[Co(NH₃)₆]³⁺ (Octahedral, Diamagnetic):
3d⁶ configuration.NH₃ is a strong ligand, so the 3d electrons pair up.3d orbitals, leading to d²sp³ hybridization.[CoF₆]³⁻ (Octahedral, Paramagnetic):
3d⁶.F⁻ is a weak ligand, so the 3d electrons do not pair up.4s, three 4p, and two 4d, leading to sp³d² hybridization.[Ni(CN)₄]²⁻ (Square Planar, Diamagnetic):
3d⁸ configuration.CN⁻ is a strong ligand, forcing one of the unpaired 3d electrons to pair up.3d orbital empty, leading to dsp² hybridization.[NiCl₄]²⁻ (Tetrahedral, Paramagnetic):
3d⁸.Cl⁻ is a weak ligand and does not cause pairing of 3d electrons.4s and three 4p orbitals, leading to sp³ hybridization.CFT is an electrostatic model that treats ligands as point charges or dipoles. It focuses on the effect of the ligand's electric field on the energies of the d-orbitals of the central metal ion.
Key Concepts:
Crystal Field Splitting in Octahedral Complexes:
d(x²-y²) and d(z²) orbitals (the e_g set), which point directly at the axes, experience more repulsion and are raised in energy.d(xy), d(yz), and d(xz) orbitals (the t₂g set), which lie between the axes, experience less repulsion and are lowered in energy.e_g and t₂g sets is the crystal field splitting energy (Δo).Spectrochemical Series: Ligands can be arranged in order of their ability to cause d-orbital splitting. This is the spectrochemical series.
I⁻, Br⁻, Cl⁻, F⁻) cause small splitting (Δo is small). They form high-spin complexes because it's energetically easier for electrons to occupy the higher e_g orbitals than to pair up in the t₂g orbitals (Δo < P, where P is pairing energy).CN⁻, CO, en, NH₃) cause large splitting (Δo is large). They form low-spin complexes because pairing up in the t₂g orbitals is energetically more favorable than moving to the high-energy e_g orbitals (Δo > P).Series (increasing strength):
I⁻ < Br⁻ < SCN⁻ < Cl⁻ < F⁻ < OH⁻ < H₂O < NH₃ < en < CN⁻ < CO
Crystal Field Splitting in Tetrahedral Complexes:
t₂ set is higher in energy, and the e set is lower.Δt) is much smaller than in octahedral fields: Δt = (4/9)Δo.Δt is small, pairing rarely occurs, and tetrahedral complexes are almost always high-spin.The color of transition metal complexes is explained by CFT.
t₂g) to a higher-energy d-orbital (e_g). This is called a d-d transition.[Ti(H₂O)₆]³⁺ is violet. Ti³⁺ has a 3d¹ configuration. The single electron is in the t₂g level. The complex absorbs blue-green light, which excites the electron to the e_g level. Since blue-green light is removed, the transmitted light appears violet.CuSO₄ is white (no ligands, no splitting), but hydrated CuSO₄·5H₂O is blue.CO can cause large splitting.Metal carbonyls are compounds with carbon monoxide (CO) as the only ligand.
Structure:
Ni(CO)₄: TetrahedralFe(CO)₅: Trigonal bipyramidalCr(CO)₆: OctahedralThe bond between the metal and carbon in metal carbonyls has both σ and π character, which creates a special strengthening effect called synergic bonding.
σ bond: A lone pair of electrons from the carbon atom of CO is donated into a vacant d-orbital of the metal.π bond (Back-bonding): A pair of electrons from a filled d-orbital of the metal is donated back into the vacant antibonding π* orbital of the CO molecule.This synergic effect strengthens the metal-carbon bond.
Coordination compounds play crucial roles in many fields:
Ca²⁺ and Mg²⁺.[Au(CN)₂]⁻. Nickel is purified via the formation and decomposition of [Ni(CO)₄].[(Ph₃P)₃RhCl], is used for the hydrogenation of alkenes.[Ag(CN)₂]⁻ and [Au(CN)₂]⁻.AgBr is removed from the film by washing with "hypo" solution, which forms the complex ion [Ag(S₂O₃)₂]³⁻.Great job reading through all sections. Ready to test your knowledge and reinforce your learning?