Light: Mirrors and LensesClass 8 Science NCERT Solutions

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Q1End-of-Chapter Questions

A light ray is incident on a mirror and gets reflected by it (Fig. 10.21). The angle made by the incident ray with the normal to the mirror is 40∘40^{\circ}. What is the angle made by the reflected ray with the mirror?

(i)

40∘40^{\circ}

(ii)

50∘50^{\circ}

(iii)

45∘45^{\circ}

(iv)

60∘60^{\circ}

Solution

Given: The angle made by the incident ray with the normal to the mirror, which is the angle of incidence (i), is 40∘40^{\circ}. Angle of incidence, i=40∘i = 40^{\circ}.
To Find: The angle made by the reflected ray with the mirror.
Principle: According to the first law of reflection, the angle of incidence is equal to the angle of reflection. i=ri = r Where rr is the angle of reflection (the angle between the reflected ray and the normal).
Solution: Using the law of reflection: Angle of reflection, r=i=40∘r = i = 40^{\circ}.
The normal is a line perpendicular to the mirror surface. Therefore, the angle between the normal and the mirror is 90∘90^{\circ}.
The angle made by the reflected ray with the mirror is the difference between the angle of the normal to the mirror and the angle of reflection. Angle with mirror = 90∘−r90^{\circ} - r Angle with mirror = 90∘−40∘=50∘90^{\circ} - 40^{\circ} = 50^{\circ}.
Final Answer: The correct option is (ii) 50∘50^{\circ}.