Key Points

Atoms and Molecules

14 Sections
  • Law of Conservation of Mass

    In a chemical reaction, the total mass of the substances that react (reactants) is equal to the total mass of the substances formed (products). This can be expressed as: massreactants=massproducts\sum \text{mass}_{\text{reactants}} = \sum \text{mass}_{\text{products}}.

  • Law of Constant Proportions

    In a pure chemical compound, the elements are always present in a definite proportion by mass. For example, in water (H2OH_2O), the mass ratio of hydrogen to oxygen is always 1:81:8.

  • Calculating Reactant Mass using Proportions

    To find the mass of one reactant needed to completely react with another, use their fixed mass ratio. If element A and B combine in a mass ratio of a:ba:b, then for a mass mAm_A of A, the required mass of B is mB=ba×mAm_B = \frac{b}{a} \times m_A.

  • Dalton's Postulate on Ratios

    A key concept from Dalton's atomic theory is that atoms combine in the ratio of small whole numbers to form compounds. This explains why the ratio of atoms in a molecule like water (H2OH_2O) is a simple 2:12:1.

  • Atomic Mass Unit Definition

    The atomic mass unit (u) is the standard unit for indicating mass on an atomic or molecular scale. It is defined as a mass exactly equal to one-twelfth the mass of one atom of carbon-12, so 1 u=112×mass of one C-12 atom1 \text{ u} = \frac{1}{12} \times \text{mass of one C-12 atom}.

  • Calculating Molecular Mass

    The molecular mass of a substance is the sum of the atomic masses of all the atoms in a single molecule of that substance. For a molecule with formula AxByA_x B_y, the molecular mass is (x×atomic mass of A)+(y×atomic mass of B)(x \times \text{atomic mass of A}) + (y \times \text{atomic mass of B}).

  • Example of Molecular Mass for Nitric Acid

    To calculate the molecular mass of nitric acid (HNO3HNO_3), sum the atomic masses: 1×(atomic mass of H)+1×(atomic mass of N)+3×(atomic mass of O)1 \times (\text{atomic mass of H}) + 1 \times (\text{atomic mass of N}) + 3 \times (\text{atomic mass of O}). This gives 1+14+3(16)=63 u1 + 14 + 3(16) = 63 \text{ u}.

  • Formula Unit Mass

    Formula unit mass is calculated in the same way as molecular mass but is used for substances whose constituent particles are ions, like ionic compounds. It is the sum of the atomic masses of all atoms in a formula unit.

  • Example of Formula Unit Mass for Calcium Chloride

    To find the formula unit mass of calcium chloride (CaCl2CaCl_2), sum the atomic masses of its ions: (1×atomic mass of Ca)+(2×atomic mass of Cl)(1 \times \text{atomic mass of Ca}) + (2 \times \text{atomic mass of Cl}). This gives 40+2(35.5)=111 u40 + 2(35.5) = 111 \text{ u}.

  • Converting Mass Ratio to Atom Ratio

    To find the simplest whole number ratio of atoms in a compound, divide the mass of each element by its atomic mass. The resulting values represent the ratio of the number of atoms.

  • Example of Atom Ratio Calculation

    In water, the mass ratio of Hydrogen to Oxygen is 1:81:8. Given atomic masses H=1u and O=16u, the ratio of atoms is (11):(816)=1:0.5(\frac{1}{1}) : (\frac{8}{16}) = 1 : 0.5. To get a whole number ratio, multiply by 2 to get 2:12:1.

  • Valency and Chemical Formula

    Valency is the combining capacity of an element. The 'criss-cross' method uses valencies to determine the chemical formula. If element A has valency xx and element B has valency yy, the formula is AyBxA_y B_x.

  • Writing Formula for Polyatomic Ions

    When a compound contains a polyatomic ion, and more than one unit of that ion is needed, the ion's formula is enclosed in parentheses with a subscript. For example, in Calcium Hydroxide, one Ca2+Ca^{2+} ion combines with two OHOH^{-} ions to form Ca(OH)2Ca(OH)_2.

  • Atomicity

    Atomicity is the number of atoms constituting a molecule. For example, oxygen gas (O2O_2) is diatomic (atomicity 2), while ozone (O3O_3) is triatomic (atomicity 3).

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