Question 1

Q1: A survey conducted by an organisation for the cause of illness and death among the women between the ages 15-44 (in years) worldwide, found the follow...

Accepted Answer

(i) Graphical Representation The given data can be represented by a bar graph. The steps to construct the bar graph are as follows: 1. Draw two perpendicular axes. Mark 'Causes' on the horizontal axis (x-axis) and 'Female fatality rate (%)' on the vertical axis (y-axis). 2. Choose a suitable scale f...

Question 2

Q2: The following data on the number of girls (to the nearest ten) per thousand boys in different sections of Indian society is given below. | Section...

Accepted Answer

(i) Bar Graph Representation The steps to construct the bar graph are as follows: 1. Draw two perpendicular axes. Represent 'Section' of society on the horizontal axis (x-axis) and 'Number of girls per thousand boys' on the vertical axis (y-axis). 2. Choose a suitable scale for the vertical axis. Si...

Question 3

Q3: Given below are the seats won by different political parties in the polling outcome of a state assembly elections: | Political Party | A  | B  | C  |...

Accepted Answer

(i) Bar Graph Representation The steps to construct the bar graph for the polling results are: 1. Draw two perpendicular axes. Represent 'Political Party' on the horizontal axis (x-axis) and 'Seats Won' on the vertical axis (y-axis). 2. Choose a suitable scale for the vertical axis. For example, 1 u...

Question 4

Q4: The length of 40 leaves of a plant are measured correct to one millimetre, and the obtained data is represented in the following table: | Length (in m...

Accepted Answer

(i) Histogram Representation The given data has discontinuous class intervals. To draw a histogram, we first need to make the class intervals continuous. The gap between consecutive class intervals is $127 - 126 = 1$. We add half of the gap (0.5) to the upper limit and subtract half of the gap (0.5)...

Question 5

Q5: The following table gives the life times of 400 neon lamps: | Life time (in hours) | Number of lamps | |----------------------|-----------------| | 30...

Accepted Answer

(i) Histogram Representation The given data has continuous class intervals of uniform width. Steps to draw the histogram: 1. Draw two perpendicular axes. Represent 'Life time (in hours)' on the horizontal axis (x-axis) and 'Number of lamps' on the vertical axis (y-axis). 2. Choose a suitable scale f...

Question 6

Q6: The following table gives the distribution of students of two sections according to the marks obtained by them: | Section A   |         | Section B...

Accepted Answer

Steps to draw the frequency polygons: 1.  Find the class marks for each interval. The class mark is the midpoint of the interval.     Class Mark = (Upper Limit + Lower Limit) / 2 | Marks   | Class Mark | Frequency (Section A) | Frequency (Section B) | |---------|------------|-----------------------|...

Question 7

Accepted Answer

Steps to draw the frequency polygons: 1.  Make the class intervals continuous. The gap between consecutive intervals is $7 - 6 = 1$. We subtract 0.5 from the lower limit and add 0.5 to the upper limit of each class. 2.  Find the class marks for the new continuous intervals. | Number of balls (Contin...

Question 8

Q8: A random survey of the number of children of various age groups playing in a park was found as follows: | Age (in years) | Number of children | |-----...

Accepted Answer

Steps to draw the histogram with varying class widths: Since the class intervals have varying widths, we need to adjust the heights (lengths) of the rectangles so that their areas are proportional to the frequencies. 1.  Calculate the width of each class. 2.  Find the minimum class width. The minimu...

Question 9

Q9: 100 surnames were randomly picked up from a local telephone directory and a frequency distribution of the number of letters in the English alphabet in...

Accepted Answer

(i) Histogram Representation The class intervals have varying widths, so we must adjust the heights of the rectangles. 1.  Calculate the width of each class. 2.  Find the minimum class width. The minimum width is 2 (for 4-6 and 6-8). 3.  Calculate the adjusted frequency for each class using the form...

S.No.	Causes	Female fatality rate (%)
1.	Reproductive health conditions	31.8
2.	Neuropsychiatric conditions	25.4
3.	Injuries	12.4
4.	Cardiovascular conditions	4.3
5.	Respiratory conditions	4.1
6.	Other causes	22.0

Section	Number of girls per thousand boys
Scheduled Caste (SC)	940
Scheduled Tribe (ST)	970
Non SC/ST	920
Backward districts	950
Non-backward districts	920
Rural	930
Urban	910

Length (in mm)	Number of leaves
118-126	3
127-135	5
136-144	9
145-153	12
154-162	5
163-171	4
172-180	2

Life time (in hours)	Number of lamps
300-400	14
400-500	56
500-600	60
600-700	86
700-800	74
800-900	62
900-1000	48

Section A		Section B
Marks	Frequency	Marks	Frequency
0-10	3	0-10	5
10-20	9	10-20	19
20-30	17	20-30	15
30-40	12	30-40	10
40-50	9	40-50	1

Number of balls	Team A	Team B
1-6	2	5
7-12	1	6
13-18	8	2
19-24	9	10
25-30	4	5
31-36	5	6
37-42	6	3
43-48	10	4
49-54	6	8
55-60	2	10

Age (in years)	Number of children
1-2	5
2-3	3
3-5	6
5-7	12
7-10	9
10-15	10
15-17	4

NCERT Solutions